datetime.md

How to increment a datetime by adding some days?

There have been several ways to do it.

Method 1: Using timedelta of datetime package

For days

from datetime import timedelta, datetime

today = datetime.today().strftime("%Y-%m-%d")
tomorrow = datetime.today() + timedelta(1)

For seconds, we can do:

from datetime import datetime, timedelta
date = datetime.now() + timedelta(seconds=[delta_value])

Depending on how you import datetime package, it could be some variants like

import datetime

datetime.datetime.now() + datetime.timedelta(days=1)

Reading more timedelta objects in the Python docs.

Method 2: Using relativedelta of python-dateutil package

from datetime import datetime
from dateutil.relativedelta import relativedelta

dt_format = '%d/%m/%Y %H:%M:%S'
print('Today: ', datetime.now().strftime(dt_format))
date_after_month = datetime.now() + relativedelta(day=1)
print('After a day:', date_after_month.strftime(dt_format))

Remember: install the required package pip install python-dateutil for this method.

How to extract the year from a Python datetime object?

It's straighforward.

import datetime
year = datetime.date.today().year
year = datetime.datetime.today().year
year = datetime.date.today().year

How to track running time of a program

import time

start = time.time()
# do massive jobs
end = time.time()
print(f"It takes {end-start:.2f} seconds to complete the massive jobs.")